【CTF】CTF中常用的脚本(转载+自写)

【CTF】CTF中常用的脚本(转载+自写)

panedioic
2019-11-20 / 0 评论 / 3 阅读 / 正在检测是否收录...

Script:

栅栏密码:

#!/usr/bin/env python
# -*- encoding: utf-8 -*-
'''
@Time    :   2018/12/23 09:55:19
@Author  :   HeliantHuS 
@Version :   1.0
@Contact :   1984441370@qq.com
'''

string = input("输入:")
frequency = [] # 获得栅栏的栏数
result_len = len(string)        # 栅栏密码的总长度  25
for i in range(2, result_len):   # 最小栅栏长度为2   逐个测试2,3,4....
    if(result_len % i == 0):        # 当栅栏密码的总长度 模 i 余数为0  则这个i就是栅栏密码的长度
        frequency.append(i)

for numberOfColumn in frequency:   # 循环可能分的栏数
    RESULT = []                 #  保存各栏数的结果
    for i in range(numberOfColumn):     #   i : 开始取值的位置
        for j in range(i, result_len, numberOfColumn):  # 开始取值, 隔栏数取一个值, 起始位置是i
            RESULT.append(string[j])
    print("".join(RESULT))

凯撒密码:

#!/usr/bin/env python
# -*- encoding: utf-8 -*-
'''
@Time    :   2018/12/23 09:56:53
@Author  :   HeliantHuS 
@Version :   1.0
@Contact :   1984441370@qq.com
'''


import string

inputStr = input("输入:").lower()
caseS1 = string.ascii_lowercase * 2
# caseS1 = string.ascii_uppercase * 2

for j in range(26):
    result_list = []
    for i, num in zip(inputStr, range(len(inputStr))):
        status = caseS1.find(i)
        if status != -1:
            result_list.append(caseS1[status + j])
        else:
            result_list.append(inputStr[num])
    print("".join(result_list), "向右偏移了{}位".format(j))

xor异或:

#!/usr/bin/env python
# -*- encoding: utf-8 -*-
'''
@Time    :   2018/12/20 14:17:59
@Author  :   HeliantHuS 
@Version :   1.0
@Contact :   1984441370@qq.com
可以进行字符串的异或运算  可xor加密也可以解密
思路就是先将要解码的字符串转换为ascii码, 然后穷举一个数字 i , 将这个数字i与字符串的ascii码进行异或运算,将结果再转换为字符串
'''

import base64

s1 = list(b'')

for i in range(200):   # 进行穷举的数字可高可低
    result = ""
    for j in range(len(s1)):
        result += chr(s1[j] ^ i)
    print(result)

ROT13:

#!/usr/bin/env python
# -*- coding: utf-8 -*-
'''
@Author  :  HeliantHuS
@Time    :  2018/12/17 8:26
@Version :  1.0
@Contact :  1984441370@qq.com
'''

import string
s1 = ""
rot13_1 = string.ascii_lowercase[:13]
rot13_2 = string.ascii_lowercase[13:]
result = []
for i in s1:
    find_1 = rot13_1.find(i.lower())
    if find_1 != -1:
        if i.isupper():
            result.append(rot13_2[find_1].upper())
            continue
        result.append(rot13_2[find_1])
    find_2 = rot13_2.find(i.lower())
    if find_2 != -1:
        if i.isupper():
            result.append(rot13_1[find_2].upper())
            continue
        result.append(rot13_1[find_2])
    if find_1 == -1 and find_2 == -1:
        result.append(i)
    
print("". join(result))

GCD:

#!/usr/bin/env python
# -*- encoding: utf-8 -*-
'''
@Time    :   2018/12/22 11:10:50
@Author  :   HeliantHuS 
@Version :   1.0
@Contact :   1984441370@qq.com
'''

def gcd(a, b):
    if b == 0:
        return a
    else:
        return gcd(b, a % b)

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HeliantHuS

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